Edexcel IGCSE Chemistry · Spec 3.9, 3.15-3.16
Rates of Reaction Required Practicals
Covers plan fair tests for rate factors, Compare marble-chip surface areas and Investigate catalysts for hydrogen peroxide decomposition.
Chemistry revision video
Rates of Reaction Required Practicals
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Explained
The rates practicals, and choosing what to measure
Every rate experiment follows one shape. Pick a factor to change, follow something that changes as the reaction proceeds, and keep everything else the same.
What varies between the practicals is only the third part, what you follow, and there are three options.
Three ways to measure a rate
Collect a gas and measure its volume, using a gas syringe or an inverted measuring cylinder over water. Record the volume every ten or fifteen seconds. This is the method for anything producing a gas, such as marble chips with acid or hydrogen peroxide decomposing.
Measure the loss of mass, standing the flask on a balance with a cotton wool plug in the neck. The gas escapes and the mass falls. This suits a reaction producing a dense gas such as carbon dioxide, since a light gas produces too small a change to measure.
Time a visible change, such as the disappearance of a cross beneath a beaker as a precipitate forms. Here the reading is a single time rather than a series of readings, and the rate is taken as one divided by that time.
The first two give you a whole curve, so you can see the reaction slowing and stopping. The third gives one number per run, which is enough to compare conditions but not enough to describe how the rate changed.
Surface area with marble chips
React calcium carbonate with dilute hydrochloric acid and collect the carbon dioxide.
Change the size of the pieces: large chips, small chips, then powder. Keep the total mass of calcium carbonate identical, along with the volume and concentration of acid and the temperature.
Equal masses matter more than they look. Using more of the powder would mean two things had changed at once, and no conclusion about surface area could be drawn from the result.
The powder reacts fastest, because breaking a solid into smaller pieces exposes more of its particles. More of the solid is in contact with the acid, so collisions happen more frequently.
What the mark scheme accepts and rejects
An Edexcel International GCSE Chemistry mark scheme asks why a powdered solid reacts faster than a lump, for two marks, and the two points are the observation and its consequence: a greater surface area, or surface area to volume ratio, and then that this increases the rate of reaction, speeds it up, or gives more frequent successful collisions, or more successful collisions per unit time.
Two instructions follow, and both are worth having.
It rejects kinetic energy for the first mark. Grinding a solid up does not make its particles move faster; only heating does that. Reaching for kinetic energy here is applying the temperature explanation to the wrong factor, and it is a common transfer error because the two questions look alike.
And it ignores dissolving faster. Powder does dissolve faster, and it is a true observation, but it is not the reason the reaction rate rises and it earns nothing.
Notice that the collision language is what the second mark is for. More frequent collisions, or more collisions per unit time. Not more collisions on its own, since a reaction that runs for longer also has more collisions in total without being any faster.
Catalysts and hydrogen peroxide
Hydrogen peroxide decomposes slowly into water and oxygen on its own. Add manganese dioxide as a catalyst and it decomposes rapidly, so the oxygen can be collected and timed.
Test the gas with a glowing splint. It relights, which identifies oxygen.
To compare catalysts, use the same volume and concentration of hydrogen peroxide and the same mass of each catalyst, and collect gas for the same length of time.
The proof that a catalyst is not used up is worth building into the plan. Filter the catalyst out afterwards, dry it and weigh it. The mass is unchanged, and it can be used again.
Reading the graph
A volume of gas against time graph starts at the origin, rises steeply, then curves and levels off at a horizontal line.
The gradient at any point is the rate at that moment. The steepest part is at the start, when the reactant concentration is highest and collisions are most frequent. The curve flattens as reactant is used up, and the flat section means the reaction has finished.
The height of that flat section is the total volume of gas produced, which depends on how much reactant there was rather than on how fast it reacted. So a catalyst makes the curve steeper without raising the final level, while doubling the amount of reactant raises the level.
That distinction between the steepness and the height is what most graph questions are really testing.
Spec 3.9, 3.15-3.16
What you need to know
- Plan fair tests for rate factors
- Compare marble-chip surface areas
- Investigate catalysts for hydrogen peroxide decomposition
Active recall
Quick check
Answer each question before opening the answer.
Name three ways to measure rate
Gas volume, mass loss or time for a visible change
Why must marble masses be equal?
To make surface area the intended independent variable
What gas forms from hydrogen peroxide?
Oxygen
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